Now for once and for all the international and U.S. editions have the exact same problems word for word, number for number on the exact same pages. The difference is that the problems are switched around on the same page in the international edition so i have to borrow a friends books and renumber the problems at the start of each new chapter, which is really well worth it if you can do something similar b/c the U.S. edition(new) costs $147+ so i saved almost 110 bucks which you can buy another book with. And seeing as the international edition is softcover, it wont be worth much to sell it back to a book store but for 40 bucks jsut write in it all you want, you can prob sell it to someone next year and get your 40 back, they get all the your notes in it too. Or just keep it for future reference, its not expensive so why not.Read full review
UPDATE! Hydromike2 is right for the most part. Until you get to the few problems that are not in the International Edition. If your school's library or a friend has a copy of the book it's an easy fix. But if procrastinate, it could be a big hassle. Again, this is just a warning... save some money and get the international edition. BE WARNED!!!! The problem sets in the international edition are DIFFERENT than the problems in the regular edition!!!! I found out the hard way after doing an entire homework!
This book goes along with the on line lecture series. Perfect.
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For those who want a solid introduction to linear algebra but don't want theorem-proof instruction, this is a good book for the price. It's well written and packs a lot of content into a relatively short book.
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Great book written by famous MIT prof. Check out his OCW videos to go with the book
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